IC CD4011 PDF

Sep 21, #Working and pin configuration of the #NAND #IC CD A door opening indicator circuit using IC gate IC and working of NAND gates. CD TRUTH TABLE. The CD is the most used CMOS chip. The CD IC has 4 gates and these can be wired to create a BUFFER, Inverter (NOT) . ooÕoo This article starts with a detailed look at the operation of the Cmos It then considers the practical use of the IC in the small alarm circuit on the .

Author: Dir Toramar
Country: Bermuda
Language: English (Spanish)
Genre: Personal Growth
Published (Last): 4 March 2004
Pages: 357
PDF File Size: 3.1 Mb
ePub File Size: 10.36 Mb
ISBN: 632-4-40326-393-4
Downloads: 18170
Price: Free* [*Free Regsitration Required]
Uploader: Vudokora

Frank Donald June 14, 1 Comment. Each NAND gate has two inputs and one output. Each output dc4011 deliver output current of about 10mA at 12V but this range can reduce as the power supply voltage reduces.

Working of CD IC – Gadgetronicx

The positive terminal of the battery was connected to the pin 14 and negative terminal of the battery was connected to the pin7. The output pins of the IC are 3,4,10,11 and input pins are 1,2,5,6,9,8,12, Now let us see how this Integrated circuit works and how can we use it for our operations.

  BLOKBOEK TAAL 8 ANTWOORDEN PDF

N4 was wired independently and there is no dependency on other gates. We can see the state of the output pins with the assigned inputs in the truth table given above. There we can see that the NAND gate gives a high output to all the input states except the input states 1,1. The combined action of the these four gates form the working of this IC Iic Let me tell you why, usage of large range of the NAND gates occupies more space cr4011 also it withdraws more power arising problems in power management to a circuit.

This IC was used since it withdraws only small power and also reduces the complexity of the circuit.

How to Build a NAND Gate Logic Circuit Using a 4011 Chip

This circuit was wired as a door open indicator which indicates the opening of door using the bulb which was connected to the output pins uc the gates.

Here in this circuit the input pins of the are connected to the supply voltage directly as shown in the diagram.

When the door was closed push button switch, it apply logic 1 to the gate input. As a result the the bulb will not glow due to low output obtained from the output pins of the gates.

  6ES7 158 0AD01 0XA0 PDF

If the door was open or it is not properly shut, logic 0 is applied to the gate input. This makes the gate to change its output state from low to high. This makes the bulb to glow indicating that the door is not properly shut.

A Beginner’s Guide To The Cmos

Quote and Order boards in minutes on: When the doors are open the gate inputs will be 1 and the output of the ic 0 which will turn the bulb off. Closing a door will input level 0 and output level 1 causing bulb to light. The following two tabs change content below. Frank Donald is an Electronics and Communication Engineer who loves building stuff in his free time.

Video games, blogging and programming are the things he loves most.

Latest posts by Frank Donald see all. Notify of all new follow-up comments Notify of new replies to all my comments.